2-(1/k)-(1/k^2)=0

Solution for 2-(1/k)-(1/k^2)=0 equation:

D( k )

k^2 = 0

k = 0

k^2 = 0

k^2 = 0

1*k^2 = 0 // : 1

k^2 = 0

k = 0

k = 0

k = 0

k in (-oo:0) U (0:+oo)

2-(1/k)-(1/(k^2)) = 0

2-k^-1-k^-2 = 0

t_1 = k^-1

2-1*t_1^2-1*t_1^1 = 0

2-t_1^2-t_1 = 0

DELTA = (-1)^2-(-1*2*4)

DELTA = 9

DELTA > 0

t_1 = (9^(1/2)+1)/(-1*2) or t_1 = (1-9^(1/2))/(-1*2)

t_1 = -2 or t_1 = 1

t_1 = -2

k^-1+2 = 0

1*k^-1 = -2 // : 1

k^-1 = -2

-1 < 0

1/(k^1) = -2 // * k^1

1 = -2*k^1 // : -2

-1/2 = k^1

k = -1/2

t_1 = 1

k^-1-1 = 0

1*k^-1 = 1 // : 1

k^-1 = 1

-1 < 0

1/(k^1) = 1 // * k^1

1 = 1*k^1 // : 1

1 = k^1

k = 1

k in { -1/2, 1 }